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Light containing the two wavelengths 400 nm and 600 nm is incident perpendicularly where λ1 > λ2. Assuming that no intensity minima are observed between λ1 and λ2, show that the integer m in Equations 37.16 and 37.17 is given by m = λ1/2(λ1 – λ2). (b) Determine the thickness of ... Fetch This Document
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